On Wed, Apr 20, 2011 at 4:41 AM, Peter Otten <__pete...@web.de> wrote:
> The assignment writes to the local namespace, the lambda function reads from
> the global namespace; this will only work as expected if the two namespaces
> are the same:
>
>>>> exec """type = 42; print filter(lambda x: x == type, [42])""" in {}, {}
> []
>>>> ns = {}
>>>> exec """type = 42; print filter(lambda x: x == type, [42])""" in ns
> [42]That must be a quirk of exec, because it works just fine without using exec, both in and out of functions, either from the interactive interpreter or from a script: Python 2.7.1 (r271:86832, Apr 2 2011, 19:44:19) [GCC 4.4.5] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> def f(): ... t = 42 ... print filter(lambda x: x == t, [42]) ... >>> f() [42] >>> t = 43 >>> print filter(lambda x: x == t, [43]) [43] So, the question for the OP: Is this file being run with execfile? Cheers, Ian -- http://mail.python.org/mailman/listinfo/python-list
