http://www.ideone.com/infch ^ Result of the below code
On 29 March 2011 19:50, Raymond Hettinger <pyt...@rcn.com> wrote:
> from collections import Counter
> from itertools import product
>
> print('\n'.join('*'*(c//2000) for _,c in sorted(Counter(map(sum,
> product(range(6), repeat=8))).items())))
>
>
> almost-normally-yours,
>
> Raymond
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