At 07:46 PM 3/20/2011, Ken D'Ambrosio wrote:
Hey, all -- I know how to match and return stuff from a regex, but I'd
like to do an if, something like (from Perl, sorry):
if (/MatchTextHere/){DoSomething();}
How do I accomplish this in Python?
You say you've done matching and accessing stuff from the regex match
result, something like this longhand:
mo = text_password_guard_re.match( text )
if mo:
text = mo.group(1) + " ******"
The above captured the match object result value and then checked
that result. If no match then the result value would be None and the
if would not execute.
The above used a pre-compiled regex and called .match() on that. You
can instead use a pattern string directly.
mo = re.match(r"foo(\d+)", text)
if mo:
text = mo.group(1) + " ******"
And if you don't need any captures (as you say) then you can just use
the call in the if directly:
if re.match(r"foo\d+", text):
print("foo multiplied!")
And the above examples used .match(), to match starting from the
beginning of the text string, but you can also use .search()
if re.search(r"foo", text):
print("foo found somewhere in text!")
To my mind Python wants to require all usages/contexts be explicit,
requiring elaborations on your intent, whereas Perl was rather more
happy to try to understand your intentions with what little you gave
it. Enter much disputation here.
Anyway, read all you can, especially any Python code you can lay your
hands on, get the mindset from that, and just code.
Thanks!
-Ken
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