On 3/16/2011 3:51 PM, Santoso Wijaya wrote:
??
Python 2.7.1 (r271:86832, Nov 27 2010, 17:19:03) [MSC v.1500 64 bit
(AMD64)] on
win32
Type "help", "copyright", "credits" or "license" for more information.
>>> import sys
>>> L = []
>>> for i in xrange(100000):
... L.append(str(i) * (1000 / len(str(i))))
...
>>> sys.getsizeof(L)
824464
This is only the size of the list object and does not include the sum of
sizes of the string objects. With 8-byth pointers, 824464 == 8*100000 +
(small bit of overhead) + extra space (for list to grow without
reallocation and copy)
>>> L = []
>>> for i in xrange(20000):
... L.append(str(i) * (5000 / len(str(i))))
...
>>> sys.getsizeof(L)
178024
== 8*20000 + extra
--
Terry Jan Reedy
--
http://mail.python.org/mailman/listinfo/python-list
