On Mon, Mar 7, 2011 at 8:38 AM, Rogerio Luz <rogeriosantos...@gmail.com>wrote:
> Hi All
>
> I'd like to pickle an object instance with all values. So I
> instanciate myClass and set some values including a list with more
> values (in the __init__), then dump to file. I realized that the
> pickled object don't saved my new list values (saved only the
> "default" value) but saved a String and an int. What I'm doing wrong?
> Thanks Rogerio
>
> $ python3 pickler.py P
> Dump: ['default', 1, 2, 3, 4, 5, 6, 7, 8, 9] TestStr 19900909
>
> $ python3 pickler.py U
> Load: ['default'] TestStr 19900909
>
> # pickler.py
>
> import sys
> import pickle
>
> class MyClass:
> teste = 0
> nome = None
> lista = ["default"]
>
> def __init__(self):
> for reg in range(1,10):
> self.lista.append(reg)
> self.nome = "TestStr"
> self.teste = 19900909
>
In this definition, you are creating a class variable then appending your
arguments to it. Pickling won't save class variables - only
instance variables. The string and int work as you are reassigning them
within the __init__ function, thereby making them instance variables.
Something like:
class MyClass:
teste = 0
nome = None
def __init__(self):
self.lista = ['default']
for reg in range(1,10):
self.lista.append(reg)
self.nome = "TestStr"
self.teste = 19900909
> #main
> def main(argv):
> if argv[1] == "P":
> with open('myClass.pickle', 'wb') as f:
> myClass = MyClass()
> print("Dump:",myClass.lista, myClass.nome, myClass.teste)
> pickle.dump(myClass, f, pickle.HIGHEST_PROTOCOL)
>
> elif argv[1] == "U":
> with open('myClass.pickle', 'rb') as f:
> myClass = pickle.load(f)
> print("Load:",myClass.lista, myClass.nome, myClass.teste)
>
> if __name__ == "__main__":
> main(sys.argv)
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