Pascal J. Bourguignon wrote:
> Xah Lee <xah...@gmail.com> writes:
>
>
> > here's a interesting toy list processing problem.
> >
> > I have a list of lists, where each sublist is labelled by
> > a number. I need to collect together the contents of all sublists
> > sharing
> > the same label. So if I have the list
> >
> > ((0 a b) (1 c d) (2 e f) (3 g h) (1 i j) (2 k l) (4 m n) (2 o p) (4
> > q r) (5 s t))
> >
> > where the first element of each sublist is the label, I need to
> > produce:
> >
> > output:
> > ((a b) (c d i j) (e f k l o p) (g h) (m n q r) (s t))
> >
> > a Mathematica solution is here:
> > http://xahlee.org/UnixResource_dir/writ/notations_mma.html
> >
> > R5RS Scheme lisp solution:
> > http://xahlee.org/UnixResource_dir/writ/Sourav_Mukherjee_sourav.work
> > _gmail.scm by Sourav Mukherjee
> >
> > also, a Common Lisp solution can be found here:
> > http://groups.google.com/group/comp.lang.lisp/browse_frm/thread/5d1d
> > ed8824bc750b?
>
> It's too complex. Just write:
>
> (let ((list '((0 a b) (1 c d) (2 e f) (3 g h) (1 i j) (2 k l) (4 m n)
> (2 o p) (4 q r) (5 s t))))
>
> (mapcar (lambda (class) (reduce (function append) class :key
> (function rest)))
> (com.informatimago.common-lisp.list:equivalence-classes list :key
> (function first)))
>
> )
>
> --> ((S T) (Q R M N) (G H) (O P K L E F) (I J C D) (A B))
Clojure:
(def groups '((0 a b)(1 c d)(2 e f)(3 g h)(1 i j)(2 k l)(4 m n)
(2 o p)(4 q r) (5 s t)))
Using group-by:
(map (fn[[k v]](flatten (map rest v))) (group-by first groups))
Using reduce:
(map #(flatten(rest %)) (reduce (fn[h [k & v]]
(merge-with concat h {k v})) {} groups))
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