Hi all, I have a Python process on Windows and would like to start a Python subprocess using the same interpreter. I wonder how to go about this?
First, I tried the obvious subprocess.Popen([ sys.executable, "subproc.py", ... ]) but that fails, because my process has a "native launcher", (i.e. C: \path\mylauncher.exe, which is just a wrapper around the Python program) and hence sys.executable returns this path instead of the interpreter location. It isn't appropriate to use the launcher for the subprocess. I also tried using sys.exec_prefix but there didn't seem to be any standard location for the interpreter under this directory in any case. I feel certain there must be some way to do this as it seems a rather basic thing somehow, can anyone give me a hint? Regards, Geoff Bache -- http://mail.python.org/mailman/listinfo/python-list
