"Octavian Rasnita" <orasn...@gmail.com> writes:
> If I want to create a dictionary from a list, is there a better way than the
> long line below?
>
> l = [1, 2, 3, 4, 5, 6, 7, 'a', 8, 'b']
>
> d = dict(zip([l[x] for x in range(len(l)) if x %2 == 0], [l[x] for x in
> range(len(l)) if x %2 == 1]))
>
> print(d)
>
> {8: 'b', 1: 2, 3: 4, 5: 6, 7: 'a'}
it = iter(l)
d = dict(izip(it, it))
izip is the iterator equivalent of zip, import it from itertools. (Or, if
your list is short, just use zip instead.)
It can be written in a single short line, at the cost of additional
obfuscation:
d = dict(izip(*[iter(l)]*2))
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