Heiko Wundram wrote:
> Am Freitag, 27. Mai 2005 13:31 schrieb Michael:
>
>>if(C == 'z') C='a';
>>else C++;
>
>
> if C == "z":
> C = "a"
> else:
> C = chr(ord(C)+1)
>
According to the OP's problem (with the assumption that only characters
from a-z are given) he might even try a lil LC:
>>> s = "shiftthis"
>>> ''.join([chr(((ord(x)-ord('a')+1)%26)+ord('a')) for x in s])
'tijguuijt'HTH, Wolfram -- http://mail.python.org/mailman/listinfo/python-list
