On Tue, 30 Nov 2010 17:08:57 -0800, Gnarlodious wrote:
> This works for me:
>
> def sendList():
> return ["item0", "item1"]
>
> def query():
> l=sendList()
> return ["Formatting only {0} into a string".format(l[0]), l[1]]
For the record, you're not actually changing a list in place, you're
creating a new list.
I would prefer:
def query():
l = sendList()
l[0] = "Formatting only {0} into a string".format(l[0])
return l
which will continue to work even if sendlist() gets changed to return 47
items instead of 2.
An alternative would be:
--
Steven
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