Thank you all for your interest in my problem. As Peter pointed out,
there was one row with zero elements in it and that's where my problem
was (of course it was the very last row, hence my confidence I have
"good" data).
Have a nice one,
Costin
On Tue, Nov 9, 2010 at 12:02 PM, Nitin Pawar <nitinpawar...@gmail.com> wrote:
> You may want to try a spilt if you are getting 8 different elements then it
> will give you a list of those elements
>
> On Tue, Nov 9, 2010 at 3:21 PM, Costin Gamenț <costin.gam...@gmail.com>
> wrote:
>>
>> Thank you for your timely response. Yes, I am sure "i" and "j" are
>> from the same iteration. I should point out that "i" actually has 8
>> elements and that str(i) gives a nice printout.
>>
>> On Tue, Nov 9, 2010 at 11:33 AM, Stefan Behnel <stefan...@behnel.de>
>> wrote:
>> > Costin Gamenț, 09.11.2010 10:24:
>> >>
>> >> Hi, I am trying to read a string as csv, but I encountered an odd
>> >> problem. Here's my code:
>> >>
>> >> csvfile = csv.reader(datastr.split('\n'), delimiter=';')
>> >> r = ''
>> >> for i in csvfile:
>> >> for j in i:
>> >> print j
>> >> print i[0]
>> >>
>> >> the "print j" statement works, but "print i[0]" returns "IndexError:
>> >> list index out of range". Am I missing something?
>> >
>> > Are you sure the output you get from the "print j" is from the same loop
>> > iteration as the "print i[0]"? Try adding "i" to the output.
>> >
>> > Stefan
>> >
>> > --
>> > http://mail.python.org/mailman/listinfo/python-list
>> >
>> --
>> http://mail.python.org/mailman/listinfo/python-list
>
>
>
> --
> Nitin Pawar
>
>
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