Steven D'Aprano <st...@remove-this-cybersource.com.au> writes: > def split(iterable, n): > iterators = [] > for i, iterator in enumerate(itertools.tee(iterable, n)): > f = lambda it, i=i: (t[i] for t in it) > iterators.append(f(iterator)) > return tuple(iterators) > > Is this the right approach, or have I missed something obvious?
I think there is no way around using tee. But the for loop looks ugly. This looks more direct to me, if I didn't mess something up: def split(iterable, n): return tuple(imap(itemgetter(i),t) for i,t in enumerate(tee(iterable,n))) -- http://mail.python.org/mailman/listinfo/python-list
