Jean-Michel Pichavant wrote:
Hi python fellows,
I'm looking to do the following :
import logging
l = logging.getLogger('aHeader')
l.handlers = []
l.addHandler(logging.StreamHandler())
l.handlers[-1].setFormatter(logging.Formatter("%(asctime)s - %(name)s
- %(message)s"))
l.error('1st line\n2nd line')
output:
2010-11-04 12:22:05,593 - aHeader - 1st line
2nd line
I'd like to get something like:
2010-11-04 12:22:05,593 - aHeader - 1st line
2nd line
I don't want to get the header on every line, otherwise I would just
need to log every lines.
Is there a simple way of doing that? anyone already gave a though on
that ?
The main problem I'm facing is that I cannot alter the log entry
itself, I don't know the size of the header and I think it would be
anti-pattern. My guess is that it should be handled in the formatter,
overriding the format method, but how do you get the header size (i.e.
the indentation size).
So if anyone has a piece of code doing that, feel free to point it to me.
Cheers,
JM
You can ignore me, I just found an acceptable solution (i think).
You guys still have been usefull because writing this mail helped me
structure my thoughts :o)
JM
PS:
class MultiLineFormatter(logging.Formatter):
def format(self, record):
str = logging.Formatter.format(self, record)
header, footer = str.split(record.message)
str = str.replace('\n', '\n' + ' '*len(header))
return str
There could be a problem if "%(message)s" is not in the formatter
string, but honestly, who would be doing that :)
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