On 10/28/2010 9:23 AM, John Posner wrote:
On 10/28/2010 12:16 PM, cbr...@cbrownsystems.com wrote:
It's clear but tedious to write:
if 'monday" in days_off or "tuesday" in days_off:
doSomething
I currently am tending to write:
if any([d for d in ['monday', 'tuesday'] if d in days_off]):
doSomething
Is there a better pythonic idiom for this situation?
Clunky, but it might prompt you to think of a better idea: convert the
lists to sets, and take their intersection.
-John
d1 = set('monday','tuesday')
days_off = set('saturday','sunday')
if not d1.isdisjoint(days_off) :
...
This is cheaper than intersection, since it doesn't have to allocate
and construct a set. It just tests whether any element in the smaller of
the two sets is in the larger one.
John Nagle
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