> So if you can, you could make sure to send the file as just bytes,
>> or if it must be a string, base64 encoded. If this is not possible
>> you can try the code below to obtain the bytes, not a very fast
>> solution, but it should work (Python 3):
>>
>>
>> MAP = {}
>> for i in range(256):
>> MAP[tmp] = eval("'\\u%04i'" % i)
>>
> >
> > # Let's say 'a' is your string
> > b''.join([MAP[c] for c in a])
> >
>
> I don't know what you're trying to do here.
>
> 1. 'tmp' is the same for every iteration of the 'for' loop.
>
> 2. A Unicode escape sequence expects 4 hexadecimal digits; the 'i'
> format gives a decimal number.
>
> 3. Using 'eval' to make a string this way is the long (and wrong) way
> to do it; chr(i) would have the same effect.
>
> 4. The result of the eval is a string, but you're performing a join
> with a bytestring, hence the exception.
Mmm, you're right. I didn't look at this carefully enough, and then made an
error in copying the source code. Sorry for that ...
Here's a solution that should work (if I understand your problem correctly):
your_bytes = bytes([ord(c) for c in your_string])
Almar
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