On 10/11/2010 09:24 AM, Fasihul Kabir wrote:
a = [0]*5
for i in range(0, 4):
for j in range(0, i):
a[i].append(j)
why the above codes show the following error. and how to overcome it.
Traceback (most recent call last):
File "<pyshell#10>", line 3, in <module>
a[i].append(j)
AttributeError: 'int' object has no attribute 'append'
Well.... What are you trying to do with the append? If you are trying
to grow the list "a" beyond the original 5 zeros you put into it, then
you need
a.append(j)
If you are trying to build a list from the two loops, then don't
pre-fill "a". Rather start with an empty list
a = []
and append to it
a.append(j)
Don't know what you want, but there is usually not a need to pre-fill an
array like this: a=[0]*5 . That looks more like declaring an array as
in C or C++ or many other languages. And I don't understand the the "5"
in that. Looking at your loops, I see that 6 passs through the inner
loop are produced:
for i in range(0, 4):
for j in range(0, i):
print i,j
1 0
2 0
2 1
3 0
3 1
3 2
In any case.
Your "a" is a list, containing integers.
a[i] indexes the list to produce an integer
a[i].append(...) attempts to append something to an integer -- an
operation that makes no sense.
--
Gary Herron, PhD.
Department of Computer Science
DigiPen Institute of Technology
(425) 895-4418
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http://mail.python.org/mailman/listinfo/python-list
