This may be a stemming from my complete ignorance of unicode, but when I do
this (Python 2.6):
s='\xc2\xa9 2008 \r\n'
and I want the ascii version of it, ignoring any non-ascii chars, I thought I
could do:
s.encode('ascii','ignore')
but it gives the error:
In [20]:s.encode('ascii','ignore')
----------------------------------------------------------------------------
UnicodeDecodeError Traceback (most recent call last)
/Users/bblais/python/doit100810a.py in <module>()
----> 1
2
3
4
5
UnicodeDecodeError: 'ascii' codec can't decode byte 0xc2 in position 0: ordinal
not in range(128)
am I doing something stupid here?
of course, as a workaround, I can do: ''.join([c for c in s if ord(c)<128])
but I thought the encode call should work.
thanks,
bb
--
Brian Blais
bbl...@bryant.edu
http://web.bryant.edu/~bblais
http://bblais.blogspot.com/
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