On 9/21/2010 11:03 PM, gburde...@gmail.com wrote:
Given
m=numpy.array([[1, 2, 3]])
I want to obtain
array([[1, 1, 1, 1, 2, 2, 2, 2, 3, 3, 3, 3]])
One way I've found to do this is:
numpy.reshape(numpy.tile(m,(4,1)),(12,1),'f').T
Another way is:
numpy.reshape(numpy.tile(m,(4,1)).flatten(1),(1,12))
Is there a simpler way to do this, without having to go jump through
so many hoops?
With a Python list
>>> l = []
>>> for rep in [[i]*4 for i in [1,2,3]]:
l.extend(rep)
>>> l
[1, 1, 1, 1, 2, 2, 2, 2, 3, 3, 3, 3]
or
>>> list(chain(*[[i]*4 for i in [1,2,3]]))
[1, 1, 1, 1, 2, 2, 2, 2, 3, 3, 3, 3]
Can you adapt that with numpy.array instead of list? Might be slower though
--
Terry Jan Reedy
--
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