On 09/07/2010 12:46 PM, Baba wrote:
word= 'even'
dict2 = {'i': 1, 'n': 1, 'e': 1, 'l': 2, 'v': 2}
Just go through each letter of word checking for its existence in
dict2. Return False if one misses, and True if you get through the
whole word:
def ...():
for c in word:
if c not in dict2:
return False #if any character is not in dict
return True # otherwise
If you know of generator expressions, and remember that True and False
are 1 and 0 respectively, then this works
def ...():
return sum(c in dict2 for c in word) == len(word)
Gary Herron
--
Gary Herron, PhD.
Department of Computer Science
DigiPen Institute of Technology
(425) 895-4418
--
http://mail.python.org/mailman/listinfo/python-list
