sajuptpm wrote:
> More details
> I have a list of tuples l = [((cpu_util,mem_util),(disk_util)),
> ((cpu_util,mem_util),(disk_util))]
> ie, l = [((30,50),(70)), ((50,20),(20))]
>
> l.sort(key=lambda x:(-x[0][0], x[1][0])) # sorting cpu_util asc and
> disk_util desc
>
> suppose i changed order that is l = [((mem_util,cpu_util),
> (disk_util)), ((mem_util,cpu_util),(disk_util))]
> So i have to change the sort code to l.sort(key=lambda x:(-x[0][1],
> x[1][0])) # sorting cpu_util asc and disk_util desc
>
>
> I want to use same (common) sort code, that must work even if i
> changed tuple order.
Use namedtuples:
from collections import namedtuple
Pair = namedtuple("Pair", "pair disk_util")
A = namedtuple("A", "cpu_util mem_util")
B = namedtuple("B", "mem_util cpu_util")
# you can safely omit this step
for class_ in A, B, Pair:
del class_.__repr__
items = [((30,50), 70), ((50,20),20)]
a = [Pair(A(x, y), z) for (x, y), z in items]
b = [Pair(B(y, x), z) for (x, y), z in items]
def sort(items):
items.sort(key=lambda x: x.pair.mem_util, reverse=True)
items.sort(key=lambda x: x.pair.cpu_util)
sort(a)
print a
sort(b)
print b
Peter
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