I can't use getroot() when using fromstring() -- as fromstring()
returns an Element, not an ElementTree object.
Yes, my root is the 'components' element, but find() seems to insist on
searching for sub-elements.
Ideally, I would like root.find('components') or
root.find('./components') to find the components element at the top-level.
I'd also like to be able to do root.find('./components/component') or
root.find('./components/component/name') and so on.
I guess I just have to check that root.tag == 'components' first, then
search for './component', './component/name' and so on. It's a bit
ugly, but heaps better than using minidom :)
Cheers, Brendan.
On 31/08/10 6:57 PM, Nitin Pawar wrote:
> Try using getroot()
>
> I think your root is components so its searching in root
>
> On Tue, Aug 31, 2010 at 2:19 PM, Brendan Simon (eTRIX)
> <brendan.si...@etrix.com.au <mailto:brendan.si...@etrix.com.au>> wrote:
>
> I am trying to use ElementTree (with Python 2.7) and can't seem to
> find elements at the top level. The find() and findall() methods
> seem to find elements within the top level, but not if it the
> elements are at the top level.
>
> How do I find top level elements ??
> Here is my code.
>
> import xml.etree.ElementTree as ET
>
> xml = '''\
> <?xml version="1.0" encoding="Windows-1252" ?>
> <components>
> <component>
> <name>Fred</name>
> <location>Australia</location>
> </component>
> </components>
> '''
>
> root = ET.fromstring( xml )
>
> ### This pattern is not found :(
> comps = root.find( './/components' )
>
> ### These patterns are found ok :)
> comp = root.find( './/component' )
> name = root.find( './/name' )
>
> print 'comps =', comps
> print 'comp =', comp
> print 'name =', name
>
>
> Thanks, Brendan.
>
>
> --
> http://mail.python.org/mailman/listinfo/python-list
>
>
>
>
> --
> Nitin Pawar
>
--
http://mail.python.org/mailman/listinfo/python-list
