Jed writes: > alphabet = ['a','b','c','ch','d','u','r','rr','o'] #this would > include the whole alphabet but I shortened it here > theword = 'churro' > > I would like to split the string 'churro' into a list containing: > > 'ch','u','rr','o'
All non-overlapping matches, each as long as can be, and '.' catches
single characters by default:
>>> import re
>>> re.findall('ch|ll|rr|.', 'churro')
['ch', 'u', 'rr', 'o']
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