We weren't really backwards; just gave a full solution to a half-stated
problem.
Bill, you've forgotten the least-lines-of-code requirement :-)
Mine's still a one-liner (chopped up so line breaks don't break it):
z = lambda cp: (int(cp[min([i for \
i in xrange(0, len(cp)) if \
cp[i].isdigit()]):])-1,
sum(((ord(cp[0:min([i for i in \
xrange(0, len(cp)) if \
cp[i].isdigit()])][x])-ord('A')+1) \
* (26 ** (len(cp[0:min([i for i in \
xrange(0, len(cp)) if \
cp[i].isdigit()])])-x-1)) for x in \
xrange(0, len(cp[0:min([i for i in \
xrange(0, len(cp)) if \
cp[i].isdigit()])]))))-1)
print z("B14")
# gives (13, 1)
Maybe brevity isn't the soul of wit after all ...
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