John Nagle wrote:
> There's got to be a better way to do this:
>
>
> def editmoney(n) :
> return((",".join(reduce(lambda lst, item : (lst + [item]) if
> item else lst,
> re.split(r'(\d\d\d)',str(n)[::-1]),[])))[::-1])
>
>
> >>> editmoney(0)
> '0'
> >>> editmoney(13535)
> '13,535'
> >>> editmoney(-14535)
> '-14,535'
> >>> editmoney(123456)
> '123,456'
> >>> editmoney(1234567890)
> '1,234,567,890'
> >>> editmoney(-1234)
> '-1,234'
>
> The basic idea here is that we want to split the string of digits
> into groups of 3 digits, aligned at the right. Because regular
> expressions are right to left, we have to reverse the string to
> do that, then reverse again at the end. s[::-1} reverses an
> interable.
>
> "split" with a capturing group introduces empty strings into the
> list. Hence the "reduce" and lambda to get rid of them.
>
> Any better ideas?
>
> (Yes, I know there's a built-in feature for this scheduled for
> Python 2.7.)
>>> locale.setlocale(locale.LC_ALL, ("en_US", "UTF-8"))
'en_US.UTF8'
>>> print locale.currency(13535, grouping=True)
$13,535.00
>>> print locale.format("%d", 13535, grouping=True)
13,535
>>> locale.setlocale(locale.LC_ALL, "")
'de_DE.UTF-8'
>>> print locale.currency(13535, grouping=True)
13.535,00 €
>>> print locale.format("%d", 13535, grouping=True)
13.535
Peter
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