On 07/28/10 08:15, wheres pythonmonks wrote:
f( *map(lambda x: int(x), struct.unpack('2s2s2s','123456')))
102
1. There is a way using unpack to get out string-formatted ints?
well, you can use
>>> s = '123456'
>>> [int(s[i:i+2]) for i in range(0, len(s), 2)]
[12, 34, 56]
>>> f(*_)
102
While your "f()" is just a boring placeholder I assume, you could
also write that as
sum(int(s[i:i+2]) for i in range(0, len(s), 2))
and skip creating f() altogether if all it does is add its arguments.
-tkc
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