A new python convert is now looking for a replacement for another perl idiom.
In particular, since Perl is weakly typed, I used to be able to use unpack to unpack sequences from a string, that I could then use immediately as integers. In python, I find that when I use struct.unpack I tend to get strings. (Maybe I am using it wrong?) def f(x,y,z): print x+y+z; f( *struct.unpack('2s2s2s','123456')) 123456 (the plus concatenates the strings returned by unpack) But what I want is: f( *map(lambda x: int(x), struct.unpack('2s2s2s','123456'))) 102 But this seems too complicated. I see two resolutions: 1. There is a way using unpack to get out string-formatted ints? 2. There is something like map(lambda x: int(x).... without all the lambda function call overhead. (e.g., cast tuple)? [And yes: I know I can write my own "cast_tuple" function -- that's not my point. My point is that I want a super-native python inline solution like (hopefully shorter than) my "map" version above. I don't like defining trivial functions.] W -- http://mail.python.org/mailman/listinfo/python-list