On 7/23/2010 2:30 PM, SeanMon wrote:
I was playing around with Python functions returning functions and the
scope rules for variables, and encountered this weird behavior that I
can't figure out.
Why does f1() leave x unbound, but f2() does not?
def f1():
x = 0
def g():
In 3.x, add
nonlocal x
x += 1
return x
return g1
You meant g
def f1():
x = 0
def g():
nonlocal x
x += 1
return x
return g
f=f1()
print(f())
print(f())
print(f())
print(f())
1
2
3
4
--
Terry Jan Reedy
--
http://mail.python.org/mailman/listinfo/python-list
