Hi, for rm1 I think something like this could work:
def rm1(prefix,txt):
regular_expresion = re.compile(r''+prefix+'(.*)')
return re.match(regular_expresion,txt).group(1)
On Tue, Jul 13, 2010 at 8:49 PM, News123 <news1...@free.fr> wrote:
> I wondered about a potentially nicer way of removing a prefix of a
> string if it exists.
>
>
> Here what I tried so far:
>
>
> def rm1(prefix,txt):
> if txt.startswith(prefix):
> return txt[len(prefix):]
> return txt
>
>
> for f in [ 'file:///home/me/data.txt' , '/home/me/data.txt' ]:
> # method 1 inline
> prefix = "file://"
> if f.startswith(prefix):
> rslt = f[len(prefix):]
> else
> rsl = f
> # method 2 as function
> rslt = rm1('file://',f)
>
>
> Is there any nicer function than above rm1()?
> Is there any nicer inline statement rhan my method 1' ?
>
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> http://mail.python.org/mailman/listinfo/python-list
>
--
Juan Andres Knebel
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