If I change "'echo "hello">> final.txt" to "ls -a >> final.txt" and add
fileName.close() before subprocess.
The result is still like:
12 25 9
85 25 12
.... # list of files
.....
How can I put the list before the number list 85 25 12?
Thank you.
On Tue, Jul 13, 2010 at 12:47 AM, Jia Hu <huji...@gmail.com> wrote:
> Thank you. I will try that.
>
> The code was simplified to show my problem. I do not use fileName as
> a variable in my code. Thanks for your reminding.
>
> On Mon, Jul 12, 2010 at 9:58 PM, MRAB <pyt...@mrabarnett.plus.com>wrote:
>
>> Jia Hu wrote:
>>
>>> Hello:
>>> I have a problem about how to generate a specific.txt file. I use the
>>> following code:
>>> #!/usr/bin/python
>>> # OS: Ubuntu
>>> import subprocess
>>> fileName = open ('final.txt', 'a')
>>> fileName.write ('%s %s %s \n' % (12,25,9))
>>> desLrr = subprocess.Popen('echo "hello" >> final.txt ', shell=True)
>>>
>>> fileName.seek(0,2)
>>> fileName.write ('%s %s %s \n' % (85,25,12))
>>> fileName.close()
>>> The above code generates the following result:
>>> 12 25 9
>>> 85 25 12
>>> hello
>>> What I want is:
>>> 12 25 9
>>> hello
>>> 85 25 12
>>> Could someone provies some suggestions about this problem?
>>> Thank you.
>>>
>>> When "echo" is called the file is still open, so the might not be able
>> to write to it. Try closing the file before starting the subprocess and
>> then reopen it afterwards.
>>
>> By the way, it slightly confusing that you call the variable "fileName",
>> but it doesn't contain the name of a file! :-)
>>
>> --
>> http://mail.python.org/mailman/listinfo/python-list
>>
>
>
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