Thank You Steve,
I am not using the urllib. I am using the xmlrpc and http modules from the
python library.
Please see the header code for the modules I am including..
from xmlrpc import client
import pprint
class ClientCertTransport(client.Transport):
def make_connection(self,host):
import http
host, extra_headers,x509 = self.get_host_info(host)
try:
HTTPS = http.HTTPS
except AttributeError:
raise NotImplementedError("your version of http does not support HTTPS")
else:
return HTTPS(host,None,'privkey.pem','resellercert.pem')
the rest of the code is just to get the result from the api....
regards
Pavan
________________________________
From: Steven D'Aprano <st...@remove-this-cybersource.com.au>
To: python-list@python.org
Sent: Sat, July 10, 2010 11:35:06 AM
Subject: Re: About new urllib.request in python 3.1.2
On Sat, 10 Jul 2010 07:06:47 -0700, pcchen wrote:
> And for the following three simple lines of code, borrowed from official
> python-doc 3.1.2:
>
>>>>from urllib.request import urlopen
>>>>response = urlopen('http://python.org/') html = response.read()
>
> They could cause this error:
>
> File "./http.py", line 3, in <module>
> from urllib.request import urlopen
> File "/usr/local/lib/python3.1/urllib/request.py", line 88, in
> <module>
> import http.client
> File "/home/pcchen/Python/http.py", line 3, in <module>
> from urllib.request import urlopen
> ImportError: cannot import name urlopen
Look at the traceback: your code executes "from urllib.request import
urlopen". That line in turn executes "import http.client". And *that*
fails, which causes the first import to fail.
It fails because you have shadowed the built-in package http with your
own module http://http.py.
Rename your file to something else ("myhttp.py") and it should just work.
--
Steven
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