On Mon, Jun 21, 2010 at 7:18 AM, shanti bhushan
<ershantibhus...@gmail.com>wrote:
> On Jun 21, 2:15 pm, Tim Golden <m...@timgolden.me.uk> wrote:
> > On 21/06/2010 09:23, shanti bhushan wrote:
> >
> > > i am using below code ,it works fine on ordinary python 26 ,but when i
> > > use this script in my python testing tool it gives me message "process
> > > cannot access the file because it is being used by other process" for
> > > the second time invoking of mongoose server.
> > > Please help me in handling this exception.
> >
> > Before I make any suggestions on the code, I might suggest that you
> > learn to wait a little. You sent three pretty much identical messages
> > within the space of three hours. Believe me: if people aren't helping,
> > it's not because they haven't seen your first message. Or the follow-up.
> > Or the one after that. It's because they don't know the answer, or
> > haven't the time to answer. Or aren't in the same timezone as you and
> > so haven't woken up yet!
> >
> > > def invoke_server2():
> > > file = open("mongoose-2.8.exe", "r")
> > > try:
> > > proc = subprocess.Popen(r'C:\WINDOWS\system32\cmd.exe /C "D:
> > > \372\pythonweb\mongoose-2.8.exe -root D:\New1\>YourOutput.txt"')
> > > except OSError:
> > > print "os error"
> > > file.close()
> > > sys.exc_clear()
> > > os.remove("mongoose-2.8.exe")
> >
> > OK. I'm not sure what you're achieving with the open ("mongoose...") line
> > and its corresponding close. In fact, I can't work out what the whole
> > exception block is achieving. I actually had to go and look up what
> > sys.exc_clear is doing -- and I don't think it's doing what you think
> > it's doing. You appear to be trapping an OS error, such as file-not-found
> > or access-denied, by trying to ignore the error and then deleting the
> > server
> > itself!
> >
> > Let's straighten some stuff out. First your Popen line could almost
> > certainly
> > be simplified to this:
> >
> > <code>
> > import subprocess
> >
> > with open ("YourOutput.txt", "w") as outf:
> > proc = subprocess.Popen (
> > [r"D:\372\pythonweb\mongoose-2.8.exe", "-root", r"D:\New1"],
> > stdout=outf
> > )
> >
> > </code>
> >
> > and to kill the proc, you can just call proc.kill ()
> >
> > Does that take you forward? Are you still seeing the "Cannot access
> file..."
> > errors?
> >
> > TJG
>
> i used below code
>
> import subprocess
> import time
> def invoke_server1():
> proc = subprocess.Popen(r'C:\WINDOWS\system32\cmd.exe /C "D:
> \372\pythonweb\mongoose-2.8.exe -root D:\New1\"')
>
>
> invoke_server1()
>
>
> time.sleep(10)
> proc.kill()
>
> this code only invokes the server but is not killing after 10 seconds.
>
> my purpose is invoke server many times with different argument and
> kill it.
> but when ever i use subprocess.Popen(r'C:\WINDOWS\system32\cmd.exe /
> c
> "taskkill /F /IM mongoose-2.8.exe >YourOutput1.txt"'
> this gives me error "process cannot access the file because it is
> being used by other process"
>
Your problem seems to be with *stdout* redirect to the same file:
">YourOutput1.txt". Windows is not like Unix like systems!
You can try, instead of redirecting to the same file, redirect each to a
separate file and use the following form:
<code>
proc = subprocess.Popen(r'C:\WINDOWS\system32\cmd.exe /C
"D:\372\pythonweb\mongoose-2.8.exe -root D:\New1\ 1>YourOutput.txt 2>&1"')
</code>
I hope it helps!
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