On Tue, Jun 15, 2010 at 8:49 AM, superpollo <ute...@esempio.net> wrote:
> goal (from e.c.m.): evaluate
> 1^2+2^2+3^2-4^2-5^2+6^2+7^2+8^2-9^2-10^2+...-2010^2, where each three
> consecutive + must be followed by two - (^ meaning ** in this context)
>
> my solution:
>
>>>> s = 0
>>>> for i in range(1, 2011):
> ... s += i**2
> ... if not (i+1)%5:
> ... s -= 2*i**2
> ... if not i%5:
> ... s -= 2*i**2
> ...
>>>> print s
> 536926141
>>>>
>
> bye
I think This one is pretty, clean, using the standard library.
pretty pythonic.
def sign_and_sqr(n):
""" return a numbers square a change the sign accordingly
if n % 5 == 0 or (n + 1) % 5 == 0:
return (n ** 2) * -1
else:
return n ** 2
result = sum([sign_and_sqr(x) for x in range(0,2011)])
print result
ok, the function has two exits, but im lazy at the moment :)
--
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Ignacio Mondino
Don't Panic
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