On Sat, 12 Jun 2010 03:05:43 -0700, Javier Montoya wrote:
> Dear all,
>
> I need to generate a vector of random float numbers between [0,1] such
> that their sum equals 1 and that are distributed non-uniformly. Is there
> any python function that generates such a vector?
You haven't explained your requirements in anywhere near enough detail.
Any of these match your description:
[1.0]
[0.0, 0.0, 0.0, 0.0, 1.0]
[0.1, 0.1, 0.1, 0.1, 0.1, 0.1, 0.1, 0.3]
[0.01, 0.01, 0.01, 0.01, 0.02, 0.02, 0.02, 0.03, 0.03, 0.84]
and many, many more. What do you mean by "non-uniformly"? Do you have any
specific distribution in mind? Do you have to have a particular number of
items?
For instance, you could do this:
L = []
total = 0.0
while total < 1:
x = random.uniform(0, 1-total)
L.append(x)
total += x
assert sum(L) == total == 1.0
--
Steven
--
http://mail.python.org/mailman/listinfo/python-list
