HI Skip:
I want to check is there any change in the instance 's methods.
>>> a=A()
>>> a2=A()
>>> a.f == a2.f
False
>>> a.f is a2.f
False
>>> a.f is a.f
False
>>>
If the instance methods are create on-the-fly, how to do that? Thanks.
Kyo
> -----Original Message-----
> From: Skip Montanaro [mailto:[EMAIL PROTECTED]
> Sent: Monday, May 16, 2005 11:09 AM
> To: kyo guan
> Cc: python-list@python.org
> Subject: Re: question about the id()
>
>
> kyo> Can someone explain why the id() return the same
> value, and why
> kyo> these values are changing?
>
> Instance methods are created on-the-fly. In your example the
> memory associated with the a.f bound method (not the same as
> the unbound method
> A.f) is freed before you reference a.g. That chunk of memory
> just happens to get reused for the bound method associated
> with a.g. Here's a
> demonstration:
>
> % python
> Python 2.5a0 (#77, May 14 2005, 14:47:06)
> [GCC 3.3 20030304 (Apple Computer, Inc. build 1671)] on darwin
> Type "help", "copyright", "credits" or "license" for more
> information.
> >>> class A(object):
> ... def f(): pass
> ... def g(): pass
> ...
> >>> a = A()
> >>> x = a.f
> >>> y = a.g
> >>> id(x)
> 17969240
> >>> id(y)
> 17969440
> >>> id(a.f)
> 17969400
> >>> id(a.g)
> 17969400
>
> Skip
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