On 2 Ιούν, 03:47, John Machin <sjmac...@lexicon.net> wrote: > On Jun 2, 1:57 am, "kak...@gmail.com" <kak...@gmail.com> wrote: > > > > > > > On Jun 1, 11:12 am, "kak...@gmail.com" <kak...@gmail.com> wrote: > > > > On Jun 1, 11:09 am, John Bokma <j...@castleamber.com> wrote: > > > > > "kak...@gmail.com" <kak...@gmail.com> writes: > > > > > On Jun 1, 10:34 am, Stefan Behnel <stefan...@behnel.de> wrote: > > > > >> kak...@gmail.com, 01.06.2010 16:00: > > > > > >> > how can i fix it, how to "ignore" the headers and parse only > > > > >> > the XML? > > > > > >> Consider reading the answers you got in the last thread that you > > > > >> opened > > > > >> with exactly this question. > > > > > >> Stefan > > > > > > That's exactly, what i did but something seems to not working with the > > > > > solutions i had, when i changed my implementation from pure Python's > > > > > sockets to twisted library! > > > > > That's the reason i have created a new post! > > > > > Any ideas why this happened? > > > > > As I already explained: if you send your headers as well to any XML > > > > parser it will choke on those, because the headers are /not/ valid / > > > > well-formed XML. The solution is to remove the headers from your > > > > data. As I explained before: headers are followed by one empty > > > > line. Just remove lines up and until including the empty line, and pass > > > > the data to any XML parser. > > > > > -- > > > > John Bokma > > > > j3b > > > > > Hacking & Hiking in Mexico - > > > > http://johnbokma.com/http://castleamber.com/-Perl&Python Development > > > > Thank you so much i'll try it! > > > Antonis > > > Dear John can you provide me a simple working solution? > > I don't seem to get it > > You're not wrong. Trysomething like this: > > rubbish1, rubbish2, xml = your_guff.partition('\n\n')
Ok thanks a lot! Antonis -- http://mail.python.org/mailman/listinfo/python-list
