On May 18, 12:04 pm, Stefan Behnel <stefan...@behnel.de> wrote: > shanti bhushan, 18.05.2010 07:18: > > > > > > > I have a sample.XML file > > the code is like this > > > <?xml version="1.0" encoding="UTF-8"?> > > <opml version="1.0"> > > <head> > > <title>My Podcasts</title> > > <dateCreated>Sun, 07 Mar 2010 15:53:26 > > > GMT</dateCreated> > > <dateModified>Sun, 07 Mar 2010 15:53:26 > > > GMT</dateModified> > > </head> > > <body> > > <TestCase name="Sprint_001"> > > <Input url="http://first.co.jp"; /> > > <Input url="http://www.google.com"; /> > > <Input url="http://www.epaper.times.india.com"; /> > > </TestCase> > > <TestCase name="Sprint_002"> > > <Input url="http://second.co.jp"; /> > > <Input url="http://www.google.com"; /> > > <Input url="http://www.epaper.times.india.com"; /> > > </TestCase> > > <TestCase name="Sprint_003"> > > <Input url="http://third.co.jp"; /> > > <Input url="http://www.google.com"; /> > > <Input url="http://www.epaper.times.india.com"; /> > > </TestCase> > > </body> > > </opml> > > > This my python code > > from xml.etree import ElementTree > > > with open('our.xml', 'rt') as f: > > tree = ElementTree.parse(f) > > > for node, value in tree.findall('.//TestCase/Input'): > > > url=node.attrib.get('url') > > print url > > > i want to print the url depending on name="sprint_001". > > for test_case in tree.findall('.//TestCase'): > if test_case.get('name') == 'sprint_002': > for input_el in test_case: > print input_el.get('url') > > Stefan- Hide quoted text - > > - Show quoted text -
Hi Stevan i tried your logic i am not getting any out put for this -- http://mail.python.org/mailman/listinfo/python-list
