Chris
Wow, that was a very fast response.
Thank you, it works (of course)...
Cheers
"Chris Rebert" <c...@rebertia.com> wrote in message
news:mailman.264.1274032106.32709.python-l...@python.org...
On Sun, May 16, 2010 at 10:36 AM, Thomas <thom1...@gmail.com> wrote:
Greetings
I am having a darn awful time trying to update a matrix:
row = dict([(x,0) for x in range(3)])
matrix = dict([(x,row) for x in range(-3,4,1)])
All the columns refer to the very same row dict (`row` obviously).
Python doesn't do any copying unless you explicitly request it.
Try:
matrix = dict([(x, dict([(x,0) for x in range(3)]) ) for x in
range(-3,4,1)])
This way, the row-creation code gets called for each column and thus
fresh row dicts are created rather than all just referencing the exact
same one row dict.
Nested comprehensions may be hard to understand, so you may wish to
write it using a function instead:
def make_row():
return dict([(x,0) for x in range(3)])
matrix = dict([(x,make_row()) for x in range(-3,4,1)])
See also
http://www.python.org/doc/faq/programming/#how-do-i-create-a-multidimensional-list
Cheers,
Chris
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