On Sat, 08 May 2010 12:15:22 -0700, Wolfram Hinderer wrote: > On 8 Mai, 20:46, Steven D'Aprano <st...@remove-this- cybersource.com.au> > wrote: > >> def get_leading_whitespace(s): >> t = s.lstrip() >> return s[:len(s)-len(t)] >> >> >>> c = get_leading_whitespace(a) >> >>> assert c == leading_whitespace >> >> Unless your strings are very large, this is likely to be faster than >> any other pure-Python solution you can come up with. > > Returning s[:-1 - len(t)] is faster.
I'm sure it is. Unfortunately, it's also incorrect. >>> z = "*****abcde" >>> z[:-1-5] '****' >>> z[:len(z)-5] '*****' However, s[:-len(t)] should be both faster and correct. -- Steven -- http://mail.python.org/mailman/listinfo/python-list