--- On Sat, 4/24/10, Steven D'Aprano <st...@remove-this-cybersource.com.au>
wrote:
> From: Steven D'Aprano <st...@remove-this-cybersource.com.au>
> Subject: Re: NameError: how to get the name?
> To: python-list@python.org
> Date: Saturday, April 24, 2010, 4:07 PM
> On Sat, 24 Apr 2010 04:19:43 -0700,
> Yingjie Lan wrote:
>
> > I wanted to do something like this:
> >
> > while True:
> > try:
> > def fun(a, b=b, c=c): pass
> > except NameError as ne:
> > name = get_the_var_name(ne)
> > locals()[name] = ''
> > else: break
>
> This won't work. Writing to locals() does not actually
> change the local
> variables. Try it inside a function, and you will see it
> doesn't work:
>
I tried this, and it worked:
Python 2.6.1 (r261:67515, Feb 11 2010, 00:51:29)
[GCC 4.2.1 (Apple Inc. build 5646)] on darwin
Type "help", "copyright", "credits" or "license" for more information.
>>> while True:
... try: print a
... except: locals()['a']="HERE YOU ARE"
... else: break
...
HERE YOU ARE
>>>
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