Peter Otten <__pete...@web.de> writes:
> OP: you may be looking for
>
>>>> a = "a bb ccc"
>>>> a[::-1].find(" ")
> 3
But you should be aware of the effeciency implications of doing
this. a[::-1] constructs a new list. It's probably faster to do e.g.:
len(a) - a.rfind(..) - 1
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