On Tue, Apr 20, 2010 at 3:40 AM, segunai <osk....@gmail.com> wrote: > On 4월20일, 오전10시16분, Chris Rebert <c...@rebertia.com> wrote: >> On Mon, Apr 19, 2010 at 6:00 PM, knifenomad <knifeno...@gmail.com> wrote: >> > i know it's not very hard to get that solution. >> > just by implementing simple function like below. >> >> > def partition(target, predicate): >> > """ >> > split a list into two partitions with a predicate >> > provided. >> > any better ideas? :) >> > """ >> > true = [] >> > false= [] >> > for item in target: >> > if predicates(item): >> > true.append(item) >> > else: >> > false.append(item) >> > return true, false >> >> > but i wonder if there's another way to do this with standard libraries >> > or .. built-ins. >> > if it's not, i'd like the list objects to have partition method like >> > string module has. >> >> (A) str.partition() has a /completely/ different meaning from your >> partition() >> (B) You'd probably have better luck getting it added to the itertools >> module since the concept is applicable to all iterables. >> [http://docs.python.org/library/itertools.html] >> >> Cheers, >> Chris >> --http://blog.rebertia.com > > yep, my mistake. i shouldn't have compared it to string's partition(). > i just wanted that convenience string.partition() has as a built-in. > anyway, thanks for itertools. :) > -- > http://mail.python.org/mailman/listinfo/python-list >
The way I would do it is probably apply filter to the list: >>> def f(x): return x % 2 != 0 and x % 3 != 0 ... >>> filter(f, range(2, 25)) [5, 7, 11, 13, 17, 19, 23] -- http://mail.python.org/mailman/listinfo/python-list
