On Apr 8, 3:21 pm, "M. Hamed" <mhels...@hotmail.com> wrote: > I have trouble with some Python concept. The fact that you can not > assign to a non-existent index in an array. For example: > > a = [0,1] > a[2] =========> Generates an error > > I can use a.append(2) but that always appends to the end. Sometimes I > want to use this array as a stack and hence my indexing logic would be > something like: > > If you are already at the end (based on your stack pointer): > use append() then index (and inc your pointer) > if not: > index directly (and inc your stack pointer) > > If feel that doing this everytime I want to add an element that I have > to check whether it exists or not is too much. Is there any simpler > way to do this? > > I know I can do something like this: > > a = numpy.zeros(MAX_STACK_SIZE) > > but I don't want to predetermine the stack size. > > Any help? > > Thanks
Well, if you never want to add intermediate data between your new element and the stack, you can just do: stack[index:index + 1] = [newelement] Regards, Pat -- http://mail.python.org/mailman/listinfo/python-list
