On Thu, Apr 8, 2010 at 7:39 PM, jorma kala <jjk...@gmail.com> wrote: > Hi, > > I'd like to call an external application (firefox) from a python program (a > PyQT GUI), but I want the external application to run in the background, I > mean I do not want my python calling program to wait till the external > subprocess terminates. > I've tried this: > > call(["firefox", "http://www.python.org";]) > > but my PyQT interface freezes until I terminate Firefox. > Is there any parameter I need to use with call so that the python calling > program doesn't wait for the termination of the subprocess? >
Use subprocess.Popen instead of directly using subprocess.call. -- regards, kushal -- http://mail.python.org/mailman/listinfo/python-list
