On Apr 6, 7:28 pm, Chris Colbert <sccolb...@gmail.com> wrote: > the proof is in the pudding: > > In [1]: a = range(10000) > > In [2]: s = set(a) > > In [3]: s2 = set(a) > > In [5]: b = range(10000) > > In [6]: a == b > Out[6]: True > > In [7]: s == s2 > Out[7]: True > > In [8]: %timeit a == b > 1000 loops, best of 3: 204 us per loop > > In [9]: %timeit s == s2 > 10000 loops, best of 3: 124 us per loop
I think you meant to set "s2 = set(b)": ===== In [1]: a = range(10000) In [2]: b = range(10000) In [3]: s1 = set(a) In [4]: s2 = set(a) In [5]: s3 = set(b) In [6]: %timeit a == b 10000 loops, best of 3: 191 us per loop In [7]: %timeit s1 == s2 10000 loops, best of 3: 118 us per loop In [8]: %timeit s1 == s3 1000 loops, best of 3: 325 us per loop ===== Cheers. -- http://mail.python.org/mailman/listinfo/python-list
