"stasz" wrote: > > hmm, there's lots of ways, huh? you can use itertools.zip instead of > > builtin zip, or do: > > > > map(None, list1, list2) > > Not!
huh? > One should try a possible solution first, > >>> l1 = range(10) > >>> l2 = range(10,20) > >>> l1 > [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] > >>> l2 > [10, 11, 12, 13, 14, 15, 16, 17, 18, 19] > >>> map(None,l1,l2) > [(0, 10), (1, 11), (2, 12), (3, 13), (4, 14), (5, 15), (6, 16), (7, 17), (8, > 18), (9, 19)] and that's different from zip in exactly what way? >>> zip(l1,l2) [(0, 10), (1, 11), (2, 12), (3, 13), (4, 14), (5, 15), (6, 16), (7, 17), (8, 18), (9, 19)] (as Gene pointed out, the only difference between map(None, ...) and zip(...) is that map() pads the shorter sequence, while zip() truncates the long sequence). </F> -- http://mail.python.org/mailman/listinfo/python-list
