Am 09.03.2010 13:02, schrieb Peter Otten:
[sum(a for a,b in zip(x,y) if b==c)/y.count(c)for c in y][1.5, 1.5, 8.0, 4.0, 4.0, 4.0] Peter
... pwned. Should be the fastest and shortest way to do it.I tried to do something like this, but my brain hurt while trying to visualize list comprehension evaluation orders ;)
Regards, Michael -- http://mail.python.org/mailman/listinfo/python-list
