yes you can also try: >>> float(a)/b 0.33333333333333331
On Thu, Mar 4, 2010 at 5:15 AM, Wells <thewellsoli...@gmail.com> wrote: > This seems sort of odd to me: > > >>> a = 1 > >>> a += 1.202 > >>> a > 2.202 > > Indicates that 'a' was an int that was implicitly casted to a float. > But: > > >>> a = 1 > >>> b = 3 > >>> a / b > 0 > > This does not implicitly do the casting, it treats 'a' and 'b' as > integers, and the result as well. Changing 'b' to 3.0 will yield a > float as a result (0.33333333333333331) > > Is there some way to explain the consistency here? Does python > implicitly change the casting when you add variables of a different > numeric type? > > Anyway, just curiosity more than anything else. Thanks! > -- > http://mail.python.org/mailman/listinfo/python-list >
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