On Feb 20, 7:00 pm, MRAB <pyt...@mrabarnett.plus.com> wrote:
> vsoler wrote:
> > Hello everyone!
>
> > I have a tuple of tuples, coming from an Excel range, such as this:
>
> > ((None, u'x', u'y'),
> > (u'a', 1.0, 7.0),
> > (u'b', None, 8.0))
>
> > I need to build a dictionary that has, as key, the row and column
> > header.
>
> > For example:
> > d={ (u'a',u'x'):1.0, (u'a',u'y'): 7.0, (u'b',u'y'):8.0 }
>
> > As you can see, if the value in the matrix is None, no key has to be
> > added to the dictionary.
>
> > Of course, my tuple of tuples is a lot bigger.
>
> > How can I possibly do this?
>
> > Thank you
>
> Does this help?
>
> matrix = ((None, u'x', u'y'),
> (u'a', 1.0, 7.0),
> (u'b', None, 8.0))
>
> for row in matrix[1 : ]:
> for col, val in zip(matrix[0][1 : ], row[1 : ]):
> print row[0], col, val
and the dictionary?
it is the ultimate goal of what I am intending...
Thank you
--
http://mail.python.org/mailman/listinfo/python-list
