On Feb 18, 4:28 am, lallous <elias.bachaal...@gmail.com> wrote: > > f = [lambda x: x ** n for n in xrange(2, 5)]
This is (pretty much) what the above code does. >>> f = [] >>> n = 2 >>> f.append(lambda x: x**n) >>> n = 3 >>> f.append(lambda x: x**n) >>> n = 4 >>> f.append(lambda x: x**n) >>> n = 5 >>> f.append(lambda x: x**n) Now, when you call f[0], you are calling "lambda x: x**n". What is "n"? You need some way of creating a new namespace and a new variable pointing to what "n" was for that iteration. Python doesn't create a namespace for every iteration like some languages may. You have to be more explicit about that. After all, what would you expect the following code to do? >>> n = 5 >>> f = [lambda x: x**n for i in range(2,5)] >>> n = 2 >>> f[0][5] Or, just call a function that will have a new namespace *for every call* and generate a function within each execution of that function (like make_power does). -- http://mail.python.org/mailman/listinfo/python-list
