Fredrik Lundh wrote:
> Max M wrote:
>
>
>>>depending on the data, it might be more efficient to store the
>>>"last seen index" in a dictionary, and sort the result on the way
>>>out (if necessary). something like
>>
>>form sets import Set
>>
>>data = list(Set([0.1,0.5,0.6,0.4,0.1,0.5,0.6,0.9]))
>
>
> read the OP's spec again.
Well if you want to haggle over minor details like a spec, it's easy to
be critical!
data = [0.1,0.5,0.6,0.4,0.1,0.5,0.6,0.9]
freqs = {}
for position in xrange(len(data)):
freqs.setdefault(data[position], []).append(position)
unique = [(value, positions[0]) for (value, positions) in freqs.items()
if len(positions) == 1]
--
hilsen/regards Max M, Denmark
http://www.mxm.dk/
IT's Mad Science
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